Enthalpy Calculator

Calculate

Dry-bulb temperature of the air state point

Relative humidity of the air (0–100%)

Overview

Specific enthalpy is the total heat content of moist air per unit mass of dry air — the sum of sensible heat carried by the air-vapor mixture and latent heat bound in the water vapor. It is the single most important quantity in HVAC coil design, because the load on any heating or cooling coil is determined entirely by the enthalpy difference between entering and leaving air multiplied by the mass flow rate through the coil.

Every psychrometric process in an air handling unit moves air from one enthalpy state to another. Cooling and dehumidification drops both dry-bulb temperature and humidity ratio, reducing enthalpy significantly. Sensible cooling alone reduces enthalpy without removing moisture. Humidification adds latent enthalpy at nearly constant sensible enthalpy. Heating adds sensible enthalpy at constant humidity ratio. In each case, the magnitude of the process is defined by Δh — the enthalpy difference between the two state points — not by temperature change alone.

This calculator implements the ASHRAE enthalpy formulation for moist air in both Imperial and Metric unit systems. It operates in two modes: single state point mode, which computes total enthalpy, sensible component, latent component, and sensible heat ratio for one air condition; and two state point mode, which computes the enthalpy difference, component breakdown, SHR, and total coil load when airflow is provided.

The humidity ratio input required for enthalpy can be derived from relative humidity, wet-bulb temperature, dew point temperature, or entered directly. All moisture input paths use the Magnus approximation for saturation pressure and the standard ASHRAE humidity ratio formula, consistent with the psychrometric equations used across this calculator suite.

How to Use This Calculator

  1. Select operating mode — choose from Single State Point, Two State Points.

  2. Enter dry-bulb temperature — in °C or °F.

  3. Select moisture input type — choose from RH, humidity ratio, wet-bulb, or dew point.

  4. Enter relative humidity — in %.

  5. Enter humidity ratio — in g/kg or gr/lb.

  6. Enter wet-bulb temperature — in °C or °F.

  7. Enter dew point temperature — in °C or °F.

  8. Enter state point 2 — dry-bulb temperature — in °C or °F.

  9. Select state point 2 — moisture input type — choose from Relative Humidity, Humidity Ratio, Wet-Bulb Temperature.

  10. Enter state point 2 — relative humidity — in %.

  11. Enter state point 2 — humidity ratio — in g/kg or gr/lb.

  12. Enter state point 2 — wet-bulb temperature — in °C or °F.

  13. Enter state point 2 — dew point temperature — in °C or °F.

  14. Enter airflow (optional) — in m³/h or CFM.

  15. Click "Calculate" — get specific enthalpy, sensible and latent components, SHR, and (in two-point mode) enthalpy difference and coil load.

Use Δh × airflow for coil load, and compare SHR against equipment-rated SHR at entering conditions.

Inputs & Outputs

Inputs

  • Operating Mode — Options: Single State Point, Two State Points (Enthalpy Difference)
  • Dry-Bulb Temperature (°C / °F)
  • Moisture Input Type — Options: Relative Humidity (%), Humidity Ratio (gr/lb), Wet-Bulb Temperature (°F), Dew Point Temperature (°F)
  • Relative Humidity (%)
  • Humidity Ratio (g/kg / gr/lb)
  • Wet-Bulb Temperature (°C / °F)
  • Dew Point Temperature (°C / °F)
  • State Point 2 — Dry-Bulb Temperature (°C / °F)
  • State Point 2 — Moisture Input Type — Options: Relative Humidity (%), Humidity Ratio (gr/lb), Wet-Bulb Temperature (°F), Dew Point Temperature (°F)
  • State Point 2 — Relative Humidity (%)
  • State Point 2 — Humidity Ratio (g/kg / gr/lb)
  • State Point 2 — Wet-Bulb Temperature (°C / °F)
  • State Point 2 — Dew Point Temperature (°C / °F)
  • Airflow (optional) (m³/h / CFM)

Outputs

  • Specific Enthalpy (h) (kJ/kg / BTU/lb)
  • Sensible Component (h_s) (kJ/kg / BTU/lb)
  • Latent Component (h_l) (kJ/kg / BTU/lb)
  • Humidity Ratio (W) (g/kg / gr/lb)
  • Sensible Heat Ratio (SHR) (%)
  • Leaving Enthalpy (h₂) (kJ/kg / BTU/lb)
  • Enthalpy Difference (Δh) (kJ/kg / BTU/lb)
  • Sensible Δh_s (kJ/kg / BTU/lb)
  • Latent Δh_l (kJ/kg / BTU/lb)
  • Process SHR (%)
  • Total Coil Load (Q) (kW / BTU/h)
  • Sensible Load (Q_s) (kW / BTU/h)
  • Latent Load (Q_l) (kW / BTU/h)

Formula

Calculator Formulas

All calculations assume standard atmospheric pressure:

  • Imperial: P_atm = 14.696 psi
  • Metric: P_atm = 101.325 kPa

Humidity Ratio from Relative Humidity

Saturation pressure (Magnus approximation):

Metric:   P_sat = 0.61078 × exp(17.625 × T / (243.04 + T))   [kPa]
Imperial: P_sat = 0.1450377 × exp(17.625 × Tc / (243.04 + Tc)) [psi]
          where Tc = (T_°F − 32) / 1.8

Vapor pressure:

P_v = (RH / 100) × P_sat

Humidity ratio:

Imperial: W = 4350 × P_v / (P_atm − P_v)    [gr/lb]
Metric:   W = 621.945 × P_v / (P_atm − P_v) [g/kg]

Enthalpy (Single State Point)

Imperial (T_db in °F, W in gr/lb, h in BTU/lb dry air):

h = 0.240 × T_db + (W / 7000) × (1061 + 0.444 × T_db)
  • Sensible: h_s = 0.240 × T_db
  • Latent: h_l = (W / 7000) × (1061 + 0.444 × T_db)
  • Note: W / 7000 converts gr/lb to lb/lb

Metric (T_db in °C, W in g/kg, h in kJ/kg dry air):

h = 1.006 × T_db + (W / 1000) × (2501 + 1.86 × T_db)
  • Sensible: h_s = 1.006 × T_db
  • Latent: h_l = (W / 1000) × (2501 + 1.86 × T_db)
  • Note: W / 1000 converts g/kg to kg/kg

Sensible Heat Ratio:

SHR = h_s / h × 100   [%]

Enthalpy Difference (Two State Points)

Δh = h₁ − h₂
Δh_s = 0.240 × (T_db1 − T_db2)   [Imperial]
Δh_s = 1.006 × (T_db1 − T_db2)   [Metric]
Δh_l = h_l1 − h_l2
SHR = Δh_s / Δh × 100   [%]

Total Coil Load (if airflow provided)

Imperial:

Q = 4.5 × CFM × Δh   [BTU/h]
Q_s = 1.1 × CFM × ΔT_db   [BTU/h]
Q_l = Q − Q_s   [BTU/h]

(4.5 = 60 min/h × 0.075 lb/ft³ standard air density)

Metric:

Q = (m³/h × Δh × 1.2) / 3600   [kW]
Q_s = (m³/h × 1.2 × 1.006 × ΔT_db) / 3600   [kW]
Q_l = Q − Q_s   [kW]

(1.2 kg/m³ = standard air density at ~20°C; divide by 3600 to convert kJ/h to kW)


Variable Reference

Variable Meaning Units
T_db Dry-bulb temperature °F / °C
W Humidity ratio gr/lb / g/kg
h Specific enthalpy BTU/lb / kJ/kg
h_s Sensible enthalpy component BTU/lb / kJ/kg
h_l Latent enthalpy component BTU/lb / kJ/kg
SHR Sensible heat ratio %
Δh Enthalpy difference BTU/lb / kJ/kg
Q Total coil load BTU/h / kW
Q_s Sensible coil load BTU/h / kW
Q_l Latent coil load BTU/h / kW
P_atm Standard atmospheric pressure 14.696 psi / 101.325 kPa

What is Enthalpy in HVAC

Specific enthalpy of moist air is the total thermodynamic energy content of a unit mass of dry air together with the water vapor it carries. In HVAC engineering it is expressed per unit mass of dry air — not per unit mass of the moist air mixture — because the mass of dry air remains constant through heating, cooling, humidification, and dehumidification processes while the mass of water vapor changes.

Enthalpy combines two physically distinct forms of energy: sensible heat, which is associated with the temperature of the air-vapor mixture and is measurable with a thermometer; and latent heat, which is the energy required to evaporate the water vapor and is not measurable by temperature alone. This distinction is critical in HVAC design because sensible and latent loads impose different demands on cooling equipment.

Main Sources of Enthalpy in HVAC Systems

  • Sensible heat — temperature-driven energy from solar gains, conduction, occupants, lighting, and equipment
  • Latent heat — moisture-driven energy from occupants, infiltration, ventilation, and process loads
  • Mixed air — combination of outdoor and return air enthalpies entering the coil
  • Supply air — conditioned air leaving the coil at design temperature and humidity

Why Enthalpy Calculation Matters

Enthalpy calculation is the foundation of HVAC coil sizing. The load on any heating or cooling coil is determined entirely by the enthalpy difference between entering and leaving air multiplied by the mass flow rate. Temperature difference alone does not capture the latent load — a coil that is correctly sized for sensible capacity but incorrectly sized for the latent fraction will fail to maintain acceptable indoor humidity.

Typical Enthalpy Ranges

Condition Imperial (BTU/lb) Metric (kJ/kg)
Winter outdoor air (0°F / −18°C, 10% RH) ~1 ~−16
Cooling supply air (55°F / 13°C, 90% RH) ~22 ~34
Comfort room air (75°F / 24°C, 50% RH) ~28 ~48
Summer outdoor, temperate (90°F / 32°C, 50% RH) ~42 ~98
Summer outdoor, hot-humid (95°F / 35°C, 60% RH) ~52 ~121

Typical SHR by Application

Application SHR Range
Office cooling (moderate humidity) 0.75–0.85
Retail / commercial 0.70–0.80
Conference room (high occupancy) 0.55–0.70
Data center / server room 0.90–1.00
Hot-humid outdoor air cooling 0.50–0.65
Gymnasium / fitness 0.55–0.70

Practical Tips

For cooling coil sizing, always use the enthalpy difference method (Q = 4.5 × CFM × Δh) rather than the sensible-only formula (Q = 1.1 × CFM × ΔT). The sensible-only formula misses the latent load entirely, which can represent 30–50% of total load in humid climates.

For equipment selection, compare the calculated SHR against the manufacturer's rated SHR at actual entering conditions. A mismatch of more than 0.10 between design SHR and equipment SHR indicates potential comfort or humidity control problems.

For energy recovery, the enthalpy difference between outdoor and exhaust air quantifies the total recoverable energy. In hot-humid climates, latent recovery can exceed sensible recovery — making enthalpy-based ERV sizing essential.

HVAC Unit Conversions

Conversion Value
1 BTU/lb 2.326 kJ/kg
1 BTU/h 0.2931 W
1 ton of refrigeration 12,000 BTU/h = 3.517 kW
7,000 grains 1 pound
1 gr/lb 0.1429 g/kg
Standard air density 0.075 lb/ft³ = 1.2 kg/m³

Key Facts

  • The enthalpy formula h = 0.240 × T_db + (W / 7000) × (1061 + 0.444 × T_db) requires W in gr/lb to be divided by 7,000 to convert to lb/lb before the latent term is applied. Omitting this division produces values 7,000 times too large — the most common manual calculation error with Imperial enthalpy.
  • Enthalpy is referenced to 0°F (Imperial) or 0°C (Metric) for dry air with zero moisture content. At 0°C and W = 0, h = 0 kJ/kg by definition. Negative enthalpy values are physically valid and occur for cold dry air below these reference temperatures.
  • The coil load formula Q = 4.5 × CFM × Δh (Imperial) assumes standard air density of 0.075 lb/ft³. At 5,000 ft elevation, actual density is approximately 0.062 lb/ft³ — the correct factor becomes approximately 3.72 instead of 4.5.
  • Sensible heat ratio (SHR) is the ratio of sensible load to total load. Cooling equipment is rated at specific SHR conditions — typically 0.75–0.80 for standard commercial equipment.
  • The latent heat of vaporization at 0°C is 2,501 kJ/kg (1,061 BTU/lb). It decreases with increasing temperature — the ASHRAE enthalpy formula captures this variation through the temperature-dependent term.
  • Enthalpy difference is the fundamental driver of energy recovery ventilation performance. An ERV with 70% total effectiveness recovers 70% of the enthalpy difference between outdoor and exhaust air — a much larger energy quantity than sensible recovery alone.

Applications

  • Cooling coil load calculation — total coil load in BTU/h equals 4.5 × CFM × Δh (Imperial) or (m³/h × Δh × 1.2) / 3600 in kW (Metric).
  • Cooling coil selection — SHR must match the load to the equipment at actual entering conditions.
  • Energy recovery ventilation sizing — total ERV load = airflow × Δh × effectiveness.
  • Economizer control logic — differential enthalpy economizer control compares outdoor air enthalpy to return air enthalpy.
  • Psychrometric process line plotting — enthalpy at each process endpoint defines the process on a psychrometric chart.
  • Equipment performance verification during commissioning — measured Δh × airflow compared against design load.

Example Calculation

Imperial Example — Two State Points, Cooling Coil

State Point 1 (Entering Air — Mixed OA/RA):

  • T_db1 = 80°F, RH1 = 55%

State Point 2 (Leaving Air — Supply Air):

  • T_db2 = 55°F, RH2 = 90%

Airflow: 5,000 CFM


State Point 1:

Tc1 = (80 − 32) / 1.8 = 26.67°C
P_sat1 = 0.1450377 × exp(17.625 × 26.67 / (243.04 + 26.67)) = 0.517 psi
P_v1 = 0.55 × 0.517 = 0.284 psi
W1 = 4350 × 0.284 / (14.696 − 0.284) = 85.7 gr/lb

h1 = 0.240 × 80 + (85.7 / 7000) × (1061 + 0.444 × 80)
h1 = 19.20 + 0.01224 × 1096.52 = 19.20 + 13.42 = 32.62 BTU/lb
h_s1 = 19.20 BTU/lb
h_l1 = 13.42 BTU/lb

State Point 2:

Tc2 = (55 − 32) / 1.8 = 12.78°C
P_sat2 = 0.1450377 × exp(17.625 × 12.78 / (243.04 + 12.78)) = 0.221 psi
P_v2 = 0.90 × 0.221 = 0.199 psi
W2 = 4350 × 0.199 / (14.696 − 0.199) = 59.7 gr/lb

h2 = 0.240 × 55 + (59.7 / 7000) × (1061 + 0.444 × 55)
h2 = 13.20 + 0.00853 × 1085.42 = 13.20 + 9.26 = 22.46 BTU/lb
h_s2 = 13.20 BTU/lb
h_l2 = 9.26 BTU/lb

Enthalpy Difference:

Δh = 32.62 − 22.46 = 10.16 BTU/lb
Δh_s = 0.240 × (80 − 55) = 6.00 BTU/lb
Δh_l = 13.42 − 9.26 = 4.16 BTU/lb
SHR = 6.00 / 10.16 × 100 = 59.1%

Coil Load:

Q = 4.5 × 5,000 × 10.16 = 228,600 BTU/h
Q_s = 1.1 × 5,000 × 25 = 137,500 BTU/h
Q_l = 228,600 − 137,500 = 91,100 BTU/h

Metric Example — Two State Points, Cooling Coil

State Point 1: T_db1 = 27°C, RH1 = 55% State Point 2: T_db2 = 13°C, RH2 = 90% Airflow: 8,500 m³/h

State Point 1:

P_sat1 = 0.61078 × exp(17.625 × 27 / (243.04 + 27)) = 3.602 kPa
P_v1 = 0.55 × 3.602 = 1.981 kPa
W1 = 621.945 × 1.981 / (101.325 − 1.981) = 12.40 g/kg

h1 = 1.006 × 27 + (12.40 / 1000) × (2501 + 1.86 × 27)
h1 = 27.16 + 0.01240 × 2551.22 = 27.16 + 31.63 = 58.79 kJ/kg

State Point 2:

P_sat2 = 0.61078 × exp(17.625 × 13 / (243.04 + 13)) = 1.498 kPa
P_v2 = 0.90 × 1.498 = 1.348 kPa
W2 = 621.945 × 1.348 / (101.325 − 1.348) = 8.39 g/kg

h2 = 1.006 × 13 + (8.39 / 1000) × (2501 + 1.86 × 13)
h2 = 13.08 + 0.00839 × 2525.18 = 13.08 + 21.19 = 34.27 kJ/kg

Enthalpy Difference:

Δh = 58.79 − 34.27 = 24.52 kJ/kg
Δh_s = 1.006 × (27 − 13) = 14.08 kJ/kg
Δh_l = 31.63 − 21.19 = 10.44 kJ/kg
SHR = 14.08 / 24.52 × 100 = 57.4%

Coil Load:

Q = (8,500 × 24.52 × 1.2) / 3600 = 69.39 kW
Q_s = (8,500 × 1.2 × 1.006 × 14) / 3600 = 39.91 kW
Q_l = 69.39 − 39.91 = 29.48 kW

Standards & References

  • ASHRAE Handbook — Fundamentals (2021), Chapter 1: Psychrometrics — Primary reference for the enthalpy formulations used on this page
  • ASHRAE Handbook — Fundamentals (2021), Chapter 18 — Defines the coil load formula Q = 4.5 × CFM × Δh based on standard air density
  • AHRI Standard 210/240-2023 — Performance rating conditions at which manufacturer SHR data is published
  • AHRI Standard 550/590-2023 — Chilled water coil rating conditions for two-state-point enthalpy calculations
  • ASHRAE Standard 90.1-2022 — Energy recovery ventilation thresholds based on outdoor air enthalpy
  • Magnus Formula (Alduchov-Eskridge, 1996) — Saturation vapor pressure approximation used for humidity ratio derivation

Limitations

  • The coil load formulas assume standard air density — 0.075 lb/ft³ (Imperial) and 1.2 kg/m³ (Metric). At 5,000 ft elevation, air density is approximately 17% lower and the Imperial factor drops from 4.5 to approximately 3.72.
  • The enthalpy formula treats specific heat of dry air and water vapor as constants: 0.240 BTU/lb·°F (1.006 kJ/kg·°C) for dry air and 0.444 BTU/lb·°F (1.86 kJ/kg·°C) for water vapor. These are accurate across the HVAC operating range but introduce small errors at temperature extremes.
  • This calculator operates at standard atmospheric pressure (14.696 psi / 101.325 kPa) only. It does not account for variations in barometric pressure due to altitude or weather.
  • Two-state-point mode computes Δh as a simple difference h1 − h2. It does not verify whether the process is physically achievable on a specific equipment type.
  • The wet-bulb to humidity ratio conversion uses a simplified psychrometric approximation. For highest accuracy at extreme conditions, use measured humidity ratio directly.

Common Mistakes to Avoid

  • Entering W in gr/lb without applying the 7,000 divisor in the Imperial enthalpy formula. The correct calculation is h = 0.240 × T_db + (W / 7000) × (1061 + 0.444 × T_db). Without dividing W by 7,000, the latent term is 7,000 times too large.
  • Using total supply airflow instead of outdoor airflow for enthalpy-based ventilation energy calculations. The enthalpy of mixed air (return plus outdoor) is the correct entering condition for a coil load calculation.
  • Confusing SHR at design conditions with SHR at rated conditions. Manufacturers publish equipment SHR at standard ARI/AHRI test conditions. If design entering conditions differ significantly, the equipment SHR at actual conditions must be obtained from the manufacturer's performance data.
  • Treating Δh as always positive. In a heating process, h_leaving > h_entering, so Δh = h1 − h2 is negative. Always confirm which state point is entering and which is leaving before interpreting the sign of Δh.
  • Using the 4.5 multiplier for non-standard density conditions. The factor 4.5 = 60 min/h × 0.075 lb/ft³ is valid at sea-level standard conditions only. At high altitude, the actual density must be calculated and substituted.
  • Forgetting that enthalpy is referenced to dry air mass, not moist air mass. When converting between mass flow and volumetric flow, specific volume (ft³/lb dry air) must be used correctly.

Frequently Asked Questions

What is the difference between sensible heat and latent heat in HVAC?
Sensible heat is the portion of enthalpy associated with air temperature — it changes when dry-bulb temperature changes. Latent heat is the portion associated with water vapor content — it represents the energy required to evaporate the moisture present in the air. In the Imperial enthalpy formula, the sensible component is 0.240 × T_db and the latent component is (W / 7000) × (1061 + 0.444 × T_db). A cooling coil must handle both: sensible cooling reduces dry-bulb temperature, while latent cooling condenses moisture below the apparatus dew point.
Why is enthalpy expressed per pound of dry air rather than per pound of moist air?
Enthalpy in HVAC is expressed per unit mass of dry air because the mass of dry air remains constant as air passes through heating, cooling, humidification, and dehumidification processes. The mass of water vapor changes but the mass of dry air does not. Using dry air as the reference mass allows enthalpy, humidity ratio, and specific volume to be tracked consistently through any psychrometric process.
What does the factor 4.5 mean in the Imperial coil load formula?
The factor 4.5 in Q = 4.5 × CFM × Δh derives from 60 minutes per hour × 0.075 lb/ft³ standard dry air density at sea level. This converts volumetric airflow in CFM to mass flow in lb/h. At elevations above sea level, the actual air density differs and the factor must be corrected — at 5,000 ft the correct factor is approximately 3.72.
What is sensible heat ratio and how do I use it for equipment selection?
Sensible heat ratio (SHR) is the fraction of total cooling load that is sensible — SHR = sensible load / total load. Cooling equipment is designed to operate at a specific SHR — typically 0.75–0.80 for commercial units. If the design SHR is significantly lower than the equipment's rated SHR, the equipment will not remove enough moisture. Equipment selection requires matching the equipment's rated SHR at actual entering conditions against the calculated design SHR.
How do I calculate enthalpy for a mixed air condition?
Mixed air enthalpy is calculated by mass-weighted averaging: h_mixed = x × h_outdoor + (1 − x) × h_return, where x is the outdoor air fraction. Use this calculator to find h_outdoor and h_return individually, then apply the weighted average. The result is the entering air enthalpy for the coil load calculation.
When does the latent component of enthalpy exceed the sensible component?
The latent component exceeds the sensible component when humidity ratio is high and dry-bulb temperature is moderate or low — typical of hot-humid outdoor air. For example, outdoor air at 95°F DB with high humidity has a latent enthalpy that can exceed sensible enthalpy, producing SHR below 0.50. This represents the most demanding dehumidification scenario for cooling coil design.
Is this calculator valid for heating applications as well as cooling?
Yes. The enthalpy formula applies equally to heating processes. In a heating application, state point 2 (leaving air) has higher enthalpy than state point 1 (entering air), so Δh = h1 − h2 is negative. The total heating load equals mass flow rate × |Δh|. In heating mode with no humidification, the latent component does not change and Δh_l = 0 — all load is sensible.
How does enthalpy relate to energy recovery ventilation sizing?
Energy recovery ventilation performance is quantified by total effectiveness: ε_total = (h_outdoor − h_supply) / (h_outdoor − h_exhaust). The recoverable energy per unit airflow equals effectiveness × Δh × mass flow rate. In hot-humid climates, latent recovery can equal or exceed sensible recovery — making total enthalpy effectiveness a much better measure of ERV performance than sensible effectiveness alone.

Frequently Used Together

Engineers often use these calculators in combination for complete project workflows:

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